4u^2+8u+4=0

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Solution for 4u^2+8u+4=0 equation: 



4u^2+8u+4=0

a = 4; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·4·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{-8}{8}=-1$

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